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hillol samanta

· started a discussion

· 1 Months ago

Doubt with answer (Question:118070.0)

If NIT students are taking 1/3 time more to complete than that of TIT, is it not 33.33% less efficiency?

Question:
At Microsoft Pvt Ltd. there are some engineering students employed as trainee engineers, belong to two eminent institutions of India. One group belong to TIT and another to NIT. Each student of TIT works for 10 hours a day till 60 days and each student of NIT works for 8 hours till 80 days on the two same projects. The ratio of number of students of TIT and that of NIT is 4 : 5 respectively. Students of which institution is slower in work and by how much?
Options:
A) Each student of TIT is 20% less efficient than that of NIT
B) Each student of NIT is 33.33% less efficient than that of TIT
C) Each student of NIT is 25% less efficient than that of TIT
D) Each student of TIT is 33.33% less efficient than that of NIT.
Solution:

TIT = NIT

4 × 10 × 60 × E1  = 5 × 8 × 80 × E2

⇒  \(\frac{E_1}{E_2}\)  =  \(\frac{4}{3}\) 

where E1  and E2 are the respective working efficiencies per hour.

∴ Each engineer from NIT is 25% less efficient than each engineer from TIT

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