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krishnakanth

· started a discussion

· 1 Months ago

doubt (Question:583154.0)

given solution is wrong. except in 1st option remaining all other options lack a perfect suqare number.for example in 2nd option for 17 it is given as BFI but is should be given as BHI.only option 1 has all the squares for their numbers i given in the form of alphabets.so option 1 is correct.please verify it and give the correct answer.

Question:

Select the odd pair from the given alternatives.

Options:
A)

(3,5,7,11,13): (I,BE,DI,ABA,AFI)

B)

(2,5,7,11,17) : (D,BE,DI,ABA,BHI)

C)

(3,7,11,17,19) :  (I,DI,ABA,BHI,CFA)

D)

(4,6,8,9,10) :  (AF,CF,FD,HA,AAA)

Solution:

Ans: (d)

Except (d), in all others, square of the numbers of first part is represented by its alphabets.

Knowledge Expert

· commented

· 1 Months ago

Dear student
Correction has been done.

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