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VIJAY SINGH

· started a discussion

· 1 Months ago

doubt (Question: 275761.0 )

ap=6 given bp=4 and we know that any perpendicular from the centre to any chord divide in two eqal parts but here ax not eqal to bx i think a should be in place of b and vice versa then it will be right here ab is 10 and ap is 6 so it is clear that ap will be longer then px =1 calculation changed ....how could you decide that ap is small as it is given ap =6

Question:

Two mutually perpendicular chords AB and CD meet at a point P inside the circle such that AP = 6 cm, PB = 4 cm and DP = 3 cm, what is the area of circle?

Options:
A)

125 π4    sq cm

B)

100 π7    sq cm

C)

125 π8    sq cm

D)

52 π2     sq cm

Solution:

Ans: (a)

  

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