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Gurdeep Kaur

· started a discussion

· 1 Months ago

Doubt (Question: 246971.0 )

in this solution a is more than 25 so it can be any number above it. it has to be 28 to satisfy the given conditions.

Question:
If the arithmetic mean of 6a and 8b is greater than 100 and a is four times of b, then the smallest possible integer value of a is –
Options:
A) 28
B) 26
C) 32
D) 24
Solution:

Ans: (b)


Vivek

· commented

· 1 Months ago

It is given smallest possible integer value of b. So 26.

Paramount

· commented

· 1 Months ago

Yet to be approved!

Paramount

· commented

· 1 Months ago

Yet to be approved!
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