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sumanta Panigrahi

· started a discussion

· 1 Months ago

doubt (Question: 188074.0 )

when this formula derived ?

Question:
In an isosceles triangle, the measure of each equal side is 10 cm and the angle between them is 45°, then area of triangle is —
Options:
A) 25 cm2
B) \(\cfrac{25}{2} \sqrt{2}\)cm2
C) 25 \(\sqrt{2}\) cm2
D) 25 \(\sqrt{3}\) cm2
Solution:
Ans: (c)


David Bhardwaj

· commented

· 1 Months ago

it was derived in 60 CE

Knowledge Expert

· commented

· 1 Months ago

The area of any triangle, isosceles or otherwise, is 1/2 times the product of two side and the sine of their included angle.
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