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sandhya

· started a discussion

· 1 Months ago

DOUBT (Question: 186247.0 )

SIR HOW WE KNOW B=60.

Question:
In \(\triangle\)ABC, \(\angle \)BAC = 90º and AB =\(\cfrac{1}{2}\) BC. Then the measure of \(\angle \)ACB is  –
Options:
A) 60º
B) 30º
C) 45º
D) 15º
Solution:
Ans: (b)


naveen

· commented

· 1 Months ago

THE THETA(ANGLE) FACING THE SIDE IS CONSIDERED AS BASE. WE HAVE GIVEN BASE=2x AND HYPOTENUSE=x , USING COS(ANGLE)= BASE\HYPOTENUSE, WE GET ANGLE=60DEGREE.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Explanation- Cos ϴ= Base/Hypotenuse,
so, we can write cosϴ= AB/BC where ϴ is a angle between AB and CB,
Now comparing
cosϴ= 1/2 (cos 60°=1/2)
Cosϴ= Cos 60°
ϴ= 60°
for Triangle
∠A+∠B+∠C = 180°
90°+60°+∠C = 180°
∠C = 180°-150°
∠C = 30°


Hope you have a great learning with us!!

All the Best,
Team Toprankers

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Explanation- Cos ϴ= Base/Hypotenuse,
so, we can write cosϴ= AB/BC where ϴ is a angle between AB and CB,
Now comparing
cosϴ= 1/2 (cos 60°=1/2)
Cosϴ= Cos 60°
ϴ= 60°
for Triangle
∠A+∠B+∠C = 180°
90°+60°+∠C = 180°
∠C = 180°-150°
∠C = 30°


Hope you have a great learning with us!!

All the Best,
Team Toprankers
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