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piyoosh roy

· started a discussion

· 1 Months ago

Doubt in the solution (Question: 247071.0 )

while calculating H it should be sq. of 4root2 instead of 4 .

Question:
The base of a right pyramid is a square of side 8 cm and lateral surface area of it is 360 cm2. What will be its volume?
Options:
A) \(\cfrac{16\sqrt{1961}}{3}\)   cm3
B) \(\cfrac{64\sqrt{1961}}{3}\)   cm3
C) \(\cfrac{32\sqrt{1961}}{3}\)    cm3
D) \(\cfrac{96\sqrt{1961}}{3}\)   cm3
Solution:

Ans: (c)


Vivek

· commented

· 1 Months ago

square misspelled as sr.

Vivek

· commented

· 1 Months ago

Distance from centre of sr to one of its side will be 4.
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