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Vipin Bihari

· started a discussion

· 1 Months ago

direct formula of sin3q,cos3q,tan3q (Question: 269928.0 )

sin3q=3-4sin^3q and cosq=4cos^3-3
so, sin3q/cos3q=tan3q
RHS is tan3q
so, tan3q-tan3q=0

Question:

  .

Options:
A)

1

B)

3

C)

0

D)

2

Solution:

Ans: (c)

  

Rathore

· commented

· 1 Months ago

sin(3q)=3sin(q)-4sin^3(q)
cos(3q)=4cos^3(q)-3cos(q)

Adityadevraj

· commented

· 1 Months ago

Incredible bro quite time saving

Surya Singh

· commented

· 1 Months ago

but they given square instead of cube

Raj keshri

· commented

· 1 Months ago

the second part is not tan3Q...tan3Q= (3tanQ-tan^3Q)/(1-3tan^2Q)
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