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Alpha One

· started a discussion

· 1 Months ago

(1/2)*AB*AC=40
So, AB = 80/9
Using Pythagoras theorem,
BC^2 = AC^2 + AB^2
= 81 + 6400/81
So, BC = 12.65

Question:
Suppose \(\Delta\)ABC be a right-angled triangle where \(\angle \)A = 90o and AD \(\perp \) BC. If \(\triangle\)ABC = 40 cm², \(\triangle\)ACD = 10 cm² and \(\overline{AC}\) = 9 cm, then the length of BC is:  
Options:
A) 12 cm 
B) 18 cm
C) 4 cm
D) 6 cm
Solution:

Ans: (b)

manikant

· commented

· 1 Months ago

even i have chosen similar method.

Sahil Singla

· commented

· 1 Months ago

there are many question in quant which doesnot follow all rules n method.. n this one is one of them.....these type of question cause big problem in paper...

Ishan

· commented

· 1 Months ago

Your solution seems right bro...

Udit Mittal

· commented

· 1 Months ago

Yet to be approved!

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