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Vaibhav bhardwaj

· started a discussion

· 1 Months ago

didn't get this. (Question: 372502.0 )

pls, someone elaborate this for me?

Question:

How many zeros are there at the end of the number obtained from 999!

Options:
A)

246

B)

247

C)

248

D)

249

Solution:

Ans: (a)


prakash deep

· commented

· 1 Months ago

for one zero one pair of 2 and 5 is required. for a regular series 5 will occur lesser times than 2...so number of times 5 will occur gives the desired result...
now how to find frequency of 5 ocuring in a series..divide the last term in d series by 5 and note the integral quotient.again divide this quotient by 5 and note the integral quotient and so on till it will be divisible by 5. now add all the noted quotients that will be the desired result.
As here
999/5=199
199/5=39
39/5=7
7/5=1
desired result=199+39+7+1=246

Santosh Rana

· commented

· 1 Months ago

This is concept of finding zeros in factorials. It's easy concept, Google it
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