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Sohil Rajput

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· 1 Months ago

chguieffugrya solution hain

Question:
In the trapezium ABCD shown below, AD BC and AB=6, BC=7, CD= 8, AD = 17, If sides AB and CD are extended to meet at E, find the measure of AED:

Options:
A) 120°
B) 100°       
C) 80°
D)

90°

Solution:

Draw CF BA

∴ CF = BA = 6 and FD = AD – AF

⇒ FD = AD –BC = 17 – 7 = 10

In ∆CFD, CF = 6, FD = 10 and CD = 8

thus, ∠FCD = 90°

⇒ ∠AED =∠FCD =90 (corresponding angles)

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