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deepankar baudh

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· 1 Months ago

deepankar baudh (Question: 196522.0 )

why u dont provide detailed solution .

Question:
The diluted wine contains only 8 litres of wine and the rest is water. A new mixture is formed whose concentrations is 30% by replacing mixture with pure wine. How many litres of mixture shall be replaced if there was initially 32 litres of water in the mixture?
Options:
A) 4 litres 
B) 5 litres 
C) 8 litres 
D) 7 litres 
Solution:
Ans: (b) 

Initial ratio of water and wine = 32 : 8  = 4 : 1

Final ratio of water and wine = 4 : 1)×7 = 28 : 7

Final ratio of water and wine = 70 : 30 = 7 : 3)×4  = 28 : 12

If total mixture is 40 litres, mixture replaced = 5 litres

Required mixture = 5 litres

deepankar baudh

· commented

· 1 Months ago

thanks sir
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