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isha mishra
· commented
· 1 Months ago
It is given in the question that BE is perpendicular to the hypotenuse AC; there is a property of right triangle for this condition as follows:
AE = AB2/AC
2 IN THE ABOVE PROPERTY IS SQUARE i.e. AE = SQUARE OF AB UPON AC
You can easily find AB AND AC, so just put the values:
AE = 6*6 /4root 3
= 3root3
Now, look into the right triangle DEA,
angle DAE = 90-30 = 60
Just apply cos60 = AE/AD
1/2 = 3root3 / AD
AD = 6ROOT3.........THE ANSWER