cos (A+B) (Question: 326253.0 )

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Neeraj Kumar

· started a discussion

· 1 Months ago

cos (A+B) (Question: 326253.0 )

cos (A+B) = CosACosB - Sin A SinB

and you have taken cos (A+B) = Sin A SinB + CosACosB

How?

your topper scores 197.5 marks always when there are a number of wrong questions..........explain how???

Question:

If $\sin α + s i n β = a$ and $\cos α + \cos β = b$ then cos $(α + β)$ is equal to

Options:

$\frac{b^{2} - a^{2}}{b^{2} + a^{2}}$

$\frac{b^{2} + a^{2}}{{2 b}^{2} + a^{2}}$

$\frac{a^{2} - b^{2}}{b^{2} + a^{2}}$

$\frac{b^{2} + a^{2}}{{2 (b}^{2} + a^{2})}$

Solution:

Ans: (a)

Neeraj Kumar

· commented

· 1 Months ago

Cos (A+B) = Cos A Cos B - Sin A Sin B and you have taken it Cos (A+B) = Cos A Cos B + Sin A Sin B

SACHIN SAINI

· commented

· 1 Months ago

Yet to be approved!

Rajesh Golder

· commented

· 1 Months ago

exactly................how??????

Sachi

· commented

· 1 Months ago

what is your answer?

Shubham Yadav

· commented

· 1 Months ago

Yet to be approved!

Amit kumar

· commented

· 1 Months ago

Bhai fake h vo sab

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cos (A+B) (Question: 326253.0 )

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