CORRECTION (Question:320138.0)

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ABHISHEK KUMAR

· started a discussion

· 1 Months ago

CORRECTION (Question:320138.0)

PLZ CORRECT YOUR OPTION

Question:

If $n^{p} - q n + \frac{1}{4}$ is to be a perfect square, the value of P and q would be:

Options:

2, 1

2, 3

2, -2

1, -1

Solution:

$\begin{matrix} {(n - \frac{1}{2})}^{2} = n^{2} - n + \frac{1}{4} \\ S o, p = 2, q = 1 \end{matrix}$

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CORRECTION (Question:320138.0)

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