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satish narayan chaudhary

· started a discussion

· 1 Months ago

correction (Question: 246938.0 )

oo bhai , how A+B+C=0.

Question:
If x + y + z = 2s, then the value of(2s - x)3 – y3– z3 - 3(2s - x)yz is –
Options:
A) 1
B) 0
C) x2 + y2 + z2
D) x + y + z
Solution:

Ans: (b)


AARAV ALAKH

· commented

· 1 Months ago

x=y=z=2
x+y+z = 2.3
s=3
Put the value & get the answer ;)

Mainak Debnath

· commented

· 1 Months ago

A+B+C=(2s-x-y-z)=(x+y+z-x-y-z)=0; given,x+y+z=2s
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