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avinash

· started a discussion

· 1 Months ago

correction (Question: 115785.0 )

answer is 7

Question:
In the adjoining figure, ACB is a right angled triangle. CD is the altitude. Circles are inscribed within the triangles ACD, BCD. P and Q are the centres of the circles. The distance PQ is (approx) :  

Options:
A) 5
B) \(\sqrt[]{50}\)
C) 7
D) 8
Solution:
Ans: (b)


Deepak

· commented

· 1 Months ago

bhai root 50 agar shai hai toh E BCD ka center hai na ki Q .....

kesi

· commented

· 1 Months ago

ans bhai root 50 hi h yhi h


sry sir

kesi

· commented

· 1 Months ago

yup bro ans should be 7


sir rply to kr do



ya rply sirf girls ko hi dete ho
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