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Shubham

· started a discussion

· 1 Months ago

half of the distance to his first left turn is : 2/2=1
so distance from initial point = (16+9)^(1/2)=5

Question:

A Tiger walks in a forest to find his Den. From his starting point he walks 2km towards his right and then walks 5 km towards his left, again walks 5 km towards left and finally he walks towards left to half the distance to his first left turn. Now, how far is he from his starting point?

Options:
A)

Approx 6 km

B)

Approx 5 km

C)

Approx 4 km

D)

Approx 2 km

Solution:

Ans: (c)

  

In triangle ∆ BAC 

AB2 = AC2 + BC2 

AB =  \(\sqrt[]{9+6.25}\) 

AB =  \(\sqrt[]{15.25}\)

AB = 4 km. Approx

Knowledge Expert

· commented

· 1 Months ago

Dear student
The first left turn is 5 km and its half will be 2.5 km.
So the answer is correct ,please observe carefully
and solve again.

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