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Vijay Sharma

· started a discussion

· 1 Months ago

CORRECT ANSWER IS √50 (Question:115785.0)

√50 answer is correct... the circle's centre were touching the line CD the answer would have been 7..bt here its not the case because both ar touching AB so PQ is not parallel to AB... PE is measured by adding the radius(roll the circle back to see it) find PQ by pythagoras. Answer is √50

Question:
In the adjoining figure, ACB is a right angled triangle. CD is the altitude. Circles are inscribed within the triangles ACD, BCD. P and Q are the centres of the circles. The distance PQ is (approx) :  

Options:
A) 5
B) \(\sqrt[]{50}\)
C) 7
D) 8
Solution:
Ans: (b)


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