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Anuj Kumar Pal

· started a discussion

· 1 Months ago

the question is not asking about co-prime pairs. So how (6,2) can be ignored.

Question:
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is – 
Options:
A) 1
B) 2
C) 3
D) 4
Solution:
Ans: (b)


Knowledge Expert

· commented

· 1 Months ago

Just understand that the HCF given is 13.

Now if you take (2, 6) as another pair then the two numbers become 13*2 and 13*6.

Now the above two numbers have an HCF of 26 (because in 2 and 6 the common factor is 2) which does not satisfy the condition of the two numbers having HCF of 13 given in the question.

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