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Deepak

· started a discussion

· 1 Months ago

confused (Question: 108565.0 )

if c does half of the work done by A+B together so according to this it should be C=1/2A+B
SO 20=1/2A+B
40 = A+B ISN'T IT ??

Question:
 A’s efficiency is half of B, and C does half of the work done by A and B consequently. If C alone does the work in 20 days, then in how many days A, B and C together can do that piece of work?
Options:
A) \(5\cfrac{2}{3}\) days
B) \(6\cfrac{2}{3}\) days
C) 6 days
D) 7 days
Solution:
Ans: (b)

C alone can do the work in 20 days

\(\therefore\) Total time taken by (A+B) to complete the work = \(\cfrac{20}{2}\) = 10 days

Hence, total time taken by (A+B+C) to complete the work


Knowledge Expert

· commented

· 1 Months ago

Dear student,
Given answer is correct.
Keep learning,
Team TR

Deepak

· commented

· 1 Months ago

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