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Avijit

· started a discussion

· 1 Months ago

Check the Solution (Question: 351233.0 )

In the solution C,D and N may or may not be collinear. So correct the figure. Though the solution is right.

Question:

AB is the hypotenuse in the right angled triangle ABC. N is a point inside the triangle which divides the triangle in three equal parts (ABN, CAN, CBN). What is the distance between the orthocentre and the point N?

Options:
A)

AB3    

B)

AB6    

C)

AB2    

D)

AB4    

Solution:

Ans: (a)


RAHUL PRASAD

· commented

· 1 Months ago

AB/2 is the Circumaradius

RAHUL PRASAD

· commented

· 1 Months ago

CN^2 = 4. (AB/2)^2 - 4/9 ( AC^2 + CB^2 + AB^2) [formula of calculating the distance between the orthocenter and the centroid of any triangle]
Either way, the answer is same. Also, the given solution is correct.

RAHUL PRASAD

· commented

· 1 Months ago

In thices case, C is the Orthocenter, N is the Centroid, D is the Circumcenter

RAHUL PRASAD

· commented

· 1 Months ago

In any triangle, the Orthocenter, the Circumcenter and the Centroid are collinear

Avijit

· commented

· 1 Months ago

Sorry I want to say that CND may or may not be the altitude.
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