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Ramkrishna Mns

· started a discussion

· 1 Months ago

Diameter of circle is a/root2 then radius will be a/2root2
Circumradius of equil triangle with side A will be A/root3
Now A/root3 =a/2root2
So A =aroot3/2root2
So finally area of equil triangle with side A will be 3root3a^2/32

Question:
What is the area of the inner equilateral triangle if the side of the outermost square is ‘a’? (ABCD is a square).

Options:
A) \(\cfrac{3\sqrt[]{3}a^2}{32}\)
B) \(\cfrac{\sqrt[]{3}a^2}{16}\)
C) \(\cfrac{5\sqrt[]{3}a^2}{32}\)
D) \(\cfrac{5\sqrt[]{3}a^2}{64}\)
Solution:
Ans: (b) \(BD=a,EF=\cfrac{a}{2}\)

\(\therefore\) area of equilateral triangle EFG \(=\cfrac{\sqrt[]{3}}{4}\left ( \cfrac {a}{2} \right )^2=\cfrac{\sqrt[]{3}a^2}{16}\)

Knowledge Expert

· commented

· 1 Months ago

@kundan

Dear Student,

Its not same, option(a) = 3/2*option(b)

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Talented Boy

· commented

· 1 Months ago

Yet to be approved!

kundan

· commented

· 1 Months ago

a option kyo nhi h

kundan

· commented

· 1 Months ago

same answer

Abhishek Shah

· commented

· 1 Months ago

same in my case :)

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