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kanav vanaik

· started a discussion

· 1 Months ago

cannot understand the solution (Question:218884.0)

cannot understand the solution

Question:

A trader sells two brands of petrol; one is Ordinary unleaded (OU) and other one is Super unleaded (SU). He mixes 12 liters of SU with 3 liters of OU and by selling this mixture at the price of SU he gets the profit of 9.09%. If the price of SU be \(\unicode{x20B9} \)48 per liter, then the price of OU is:

Options:
A) \(\unicode{x20B9} \)38 per litre
B) \(\unicode{x20B9} \)42 per litre
C) \(\unicode{x20B9} \)28 per litre
D) \(\unicode{x20B9} \)35 per litre
Solution:

SP = \(\cfrac{12}{11}\)of CP

48 =\(\cfrac{12}{11}\) of CP ⇒   CP = 44

Now, by allegation

(Since ration of SU to OU =\(\cfrac{12}{3}\)= 4 : 1)



∴k = 44 – 16 = 28

Thus the price of  OU is Rs. 28/liter.

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