CLEAR
Toprankers-Info

+91 7676564400

Mobile App

Get it on Google Play
Discussions
Select Date
Tags:

Articles

Discussions
Submit Discussion
Navindra Kumar

· started a discussion

· 1 Months ago

calculation mistake (Question: 83313.0 )

1/3 *3/2 =1/2 hr

Question:

A is twice as fast as B and B is thrice as fast as C is. The journey covered by C in 3/2 hours will be covered by A in _____. 

Options:
A) 15 minutes
B) 20 minutes
C) 30 minutes
D) 1 hour
Solution:

Ans: (a)

Let x kmph be the speed of B. 

Let 2x kmph be the speed of A.

Speed of C = x/3  kmph

(Speed of A)/(Speed of C) = \(\frac{2x}{(\frac{x}{3})}\) = 6

Required time = \(\frac{(\frac{1}{6})}{(\frac{3}{2})}\)  hrs.

= \(\frac{1}{3}\times\frac{3}{2}\)=\(\frac{1}{4}\)  hrs. = 15 min.

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Let Speed of C = x km/h
Therefore Speed of B = 3x km/h
And Speed of A = 6x km/h
Ratio of speed of A,B,C = 6:3:1
Ratio of speed of A,C = 6:1
And thus Ratio of time of A,C = 1:6
-logo
We at aim to provide most comprehensive content & test for practice which is carefully divided into various chapters and topics to help you focus on your weak areas.Our Practice mock test gives you unmatched analytics to help you realize your strong areas,time management and improvement areas.Our Short & Crisp notes on each topic will help you to quickly revise the topic along with the tips & tricks of the exams.
More About
-Info
-Info

Mobile App

Get it on Google Play
About Us Campus Ambassador Careers Contact Us Refund Policy

All Rights Reserved Top Rankers

User Policy
Disclaimer
Terms & Conditions