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Bishruta Bhowal

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· 1 Months ago

4665-1305= 3360
6905-4665= 2240
6905-1305=5600

HCF= 560
N= 5+6+0= 11

Options are incorrect and solution also

Question:

Let N be the greatest number that will divide 1305, 4665 and 6905, leaving the same remainder in each case. Then sum of the digits in N is –

Options:
A)

9

B)

4

C)

7

D)

8

Solution:

Ans: (c)

(4665 – 1305), (6905 – 1305), (6905 – 4665)

3360, 5600, 2240

HCF of the number = 1120

Sum of number = 4

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