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Shiv Kumar Chhetri

· started a discussion

· 1 Months ago

Bhai answer correct hai (Question: 309155.0 )

Solve karo
S=9s2+10s1
(600s-600s1)/(s1+s2)

Question:

Two men are walking towards each other alongside a railway track. A freight train overtakes one of them in 20 seconds and exactly 10 minutes later meets the other man coming from the opposite direction. The train passes this man in 18 seconds. Assume the velocities are constant throughout. How long after the train has passed the second man will the two men meet?

Options:
A)

89.7 minutes

B)

90 minutes

C)

90.3 minutes

D)

91 minutes

Solution:

Ans: (b)

  

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