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alok sharma

· started a discussion

· 1 Months ago

better solution (Question: 252307.0 )

(p)........(r)........(q)

since A takes 2.6 times than normal.
so suppose normally he will travel from p to q in 10 mintues.
now he takes 26 minutes. or we can say that his normal times is 5 minutes and due to lift it is 13 minutes..

extra 8 minutes are due to travelling from r to p and p to r. so p to r he takes 4 minutes. hence r to q 1 minute.

they meet at r it means after 4 mins.

so to travel r to q , A takes 1 min and B takes 4 mins

so for the same distance , their speed will be inversely proportional to time taken

so speed ratio of A and B will be 4:1

Question:
Two people A and B start moving from P and Q that are 200 Km apart, towards each other. A is on bike and B on foot. They meet at a point R when A gives B a lift to P and returns to his original path to reach Q. On reaching Q he finds that he has taken 2.6 times his normal time. B on the other hand, realizes that he has saved 40 minutes over his normal travel time. Find the ratio of their speeds.
Options:
A) 4 : 3
B) 4 : 1
C) 3 : 1
D) 3 : 2
Solution:

Ans: (b) 

According to the question,

A takes 2.6 times more time than usual

So he has travelled a total distance = 2.6 × 200 = 520 Km

So, A had travelled 320 Km more distance due to P to R and R to P.

Distance P to R = 320/2 = 160 Km

 Q to R = 40 Km

Ratio of speed = 160 : 40 = 4 : 1

SAURABH KUMAR

· commented

· 1 Months ago

How we may conclude that b takes 4 minutes from q to r
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