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VIJAY KUMAR

· started a discussion

· 1 Months ago

(1/2)20×10×sin@=80
Sin@=4/5
Cos@=3/5
Now apply cosine rule

3/5=(400+100-side^2)/2*20*10

Side=√260

Question:
Sandeep has a triangle in which longest side is 20 cm and another side is 10 cm. Its area is 80 cm2. What is the length of the third side?
Options:
A) \(\sqrt{250}\)  cm 
B) \(\sqrt{260}\)  cm 
C) \(\sqrt{240}\)  cm 
D) \(\sqrt{270}\)  cm 
Solution:

Ans: (b)


Kumar Gaurav

· commented

· 1 Months ago

good attempt

ABHIJITH P M

· commented

· 1 Months ago

20 as base
h=8
AB =root(14^2 + 8^2)

AMAR

· commented

· 1 Months ago

great....vijay........

Sohil Rajput

· commented

· 1 Months ago

pradeep kumar etna achi english hain to cat do varna chup raho

Pradeep Kumar

· commented

· 1 Months ago

Yes Bro. It is, kudos!!

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