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BRIJESH PRAJAPATI

· started a discussion

· 1 Months ago

B (Question:271972.0)

Sophisticated qsn

Question:

If (1 – cot 4º) (1 – cot 5º) (1 – cot 6º) …. (1 – cot 41º) = 2P, then the value of P is –

Options:
A)

17

B)

18

C)

19

D)

21

Solution:

Ans: (c)


Knowledge Expert

· commented

· 1 Months ago

Dear Student,

In LHS there are 38 terms.

cot 45 = cot(41+4)
1 = ( cot 41 cot4 - 1) / (cot 41 + cot 4)
cot 41 + cot 4 = cot41 cot4 - 1
cot41 cot4 - cot41-cot4= 1
Add 1 both sides form equation you will get

(1-cot4) (1-cot41) = 2

similarly there are 19 pairs .

Therefore p = 19

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