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shantanu moria

· started a discussion

· 1 Months ago

b (Question: 113851.0 )

put x=1

Question:
The + ve square root of (x2 + 2x - 1) + \(\cfrac{1}{(x^2+2x+1)}\) is:  
Options:
A) (x + 1) + \(\cfrac{1}{(x + 1)}\)
B) (x + 1) - \(\cfrac{1}{(x + 1)}\)
C) (x + 2) - \(\cfrac{1}{(x + 1)}\)
D) (x + 2) + \(\cfrac{1}{(x + 1)}\)
Solution:
Ans: (b) Given expression

\(\therefore\) required + ve square root


Knowledge Expert

· commented

· 1 Months ago

Dear Student
The solution is of the more generalized manner. Sure you can put any value including 1,2........................n
Keep Solving
Regards
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