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saurav meena

· started a discussion

· 1 Months ago

area kese find out kiya he (Question: 188729.0 )

please explain

Question:
There is a pyramid on a base which is a regular hexagon of side 2a cm. If every slant edge of this pyramid is of length \(\cfrac{5a}{2}\) cm, then the volume of this pyramid is
Options:
A) \(3a^{3}cm^{3}\)
B) \(3\sqrt[]{2}a^{3} cm^{3}\)
C) \(3\sqrt[]{3}a^{3}cm^{3}\)
D) \(6a^{3} cm^{3}\)
Solution:

Ans: (c)

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

Area of the base = 6 * area of an equilateral triangle

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Shakshi Joshi

· commented

· 1 Months ago

A hexagon consists of 6 equilateral triangle..
otherwise you can use this formula.. Area of a regular polygon= ((a^2)/4 )* n* cot(pi/n) ; where 'a' is the length of side and 'n' is the number of sides of the polygon

saurav meena

· commented

· 1 Months ago

regular hexagon ka area kese nikala he
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