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Ambarish Gupta

· started a discussion

· 1 Months ago

any short cut (Question: 285142.0 )

convey if there is any shot method for this..

Question:

A train during its journey meets the accident twice. First accident occurs after travelling 150 km. As a result of which its speed reduced to  23    of its original speed. After travelling 200 km more, it again met with accident and its speed becomes   13   rd of its original speed. Due to that the train reached its destination 9 hours late. Had the accident occurred after travelling 50 km more in both accidents, it would have saved 2 hours, find the speed of the train.

Options:
A)

85 km/h

B)

87 km/h

C)

87.5 km

D)

90 km/h

Solution:

Ans: (c)

  

SURESH CHOUDHARY

· commented

· 1 Months ago

Speed 3x 2x and x
In first condition 50km more is traveled by speed of 3x
And 50km by speed of 2x
Due to that in second condition 100km less is traveled by speed of x
So we can say that
100/x - 50/3x - 50/2x = 2hour
3x =87.5km/h

SURESH CHOUDHARY

· commented

· 1 Months ago

Speed 3x 2x and x after accident
In first condition 50km more is traveled by speed of 3x

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
There is no shortcut for this question, the question is slight complex so it is advisable to go through general
approach.

Thanks and Regards
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