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Shashank Shah

· started a discussion

· 1 Months ago

Any other method for this question (Question: 108738.0 )

Please suggest a simple method for the above question

Question:

If \(x = \sqrt[]{6}-\sqrt[]{5}, y = \sqrt[]{5}-2, z = 2-\sqrt[]{3}\), then which of the following is true?

Options:
A) y < x < z
B) x < z < y
C) y < z < x
D) x < y < z
Solution:

Ans(D)

x = \(\sqrt[]{6}-\sqrt[]{5}= 0.2134 \)

y = \(\sqrt[]{5} - 2 =0.2360\)

z = \(2-\sqrt[]{3}= 0.2679\)

Therefore x<y<z

Nikhil Kumar

· commented

· 1 Months ago

thanx nadeem

Nadeem Ahmed Khan

· commented

· 1 Months ago

multiply the numbers ,all the numbers should be in root.......so 6x5,5x4,4x3.......lowest value will be the greatest one..........is sign between the root is plus ,highest value will be the highest
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