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Indrajit Saha

· started a discussion

· 1 Months ago

Answer Wrong (Question: 117161.0 )

As, the equation stated in question has RHS as 4 but in the solution part, you have taken RHS as 8, so the answer changed from 7/16 to 7/32

Question:
If 2x = 4y = 8z and \(\cfrac{1}{2x}+\cfrac{1}{4y}+\cfrac{1}{4z}=4\),then the value of x is:
Options:
A) \(\cfrac{7}{16}\)
B) \(\cfrac{7}{32}\)
C) \(\cfrac{7}{20}\)
D) None of these
Solution:
Ans: (b) 2x = 4y = 8z

2x = 22y = 23z

x = 2y = 3z = k

\(x=k,y=\cfrac{k}{2},z=\cfrac{k}{3}\)

substituting these value in 


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