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Ashish hiralkar

· started a discussion

· 1 Months ago

answer should be 90 (Question: 186056.0 )

answer should be 90

Question:
A man whose bowling average is 12.4, takes 5 wickets for 26 runs and there by decreases his average by 0.4. The number of wickets taken by him before his last match is?
Options:
A) 64
B) 72
C) 80
D) 85
Solution:
Ans: (d) Let He has taken x wickets before the match.

And runs given with the average 12.4, So total run given was,

= 12.4x
Runs given including this match,

12.4x+26 with the average of 12.

Now,
(12.4x+26)/(x+5) = 12
12.4x+ 26 = 12x + 60
0.4x= 34
x = 85 wickets

Knowledge Expert

· commented

· 1 Months ago

Dear Student,

85 is the only correct answer. You will be doing mistake somewhere while solving.

Suppose He has taken X wickets before the match.
And runs given with the average 12.4, So total run given was,
= 12.4X
Runs given including this match,
12.4X +26 with the average of 12.
Now,
(12.4X+26)/(X+5) = 12
12.4X + 26 = 12X + 60
0.4X = 34
X = 85 wickets

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