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Saurabh Jat

· started a discussion

· 1 Months ago

answer should be -1<x<3 (Question: 69407.0 )

log of 0 is also not possible.(it is not infinite)
x+1>0
so x>-1(only greater than, not equal or greater than)

Question:
If log2 (x + 1) < 2 ,then
Options:
A) x < 3
B) -1 \(<\) x < 3
C) x > 3
D) x > 3, x \(\leq\) -1
Solution:
Ans: (b) log2 (x + 1) < 2

\(\Rightarrow\) 22 > x + 1

\(\Rightarrow\) 4 > x + 1

\(\Rightarrow\) 3 > x                 ... (1)

But log of zero and negative number are not possible.

\(\therefore\) x + 1 \(>\) 0

\(\Rightarrow\) x \(>\) -1               ... (2)

Combining (1) and (2)

-1 \(<\) x < 3.

Knowledge Expert

· commented

· 1 Months ago

Ans: (b) log_2 (x + 1) < 2
⇒ 22 > x + 1
⇒ 4 > x + 1
⇒ 3 > x ... (1)
But log of zero and negative number are not possible.
∴ x + 1 > 0
⇒ x > -1 ... (2)
Combining (1) and (2)
-1 < x < 3.

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