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chandranshu

· started a discussion

· 1 Months ago

answer (Question: 382332.0 )

answer should be 144/50

Question:

Find the area of the largest square that can be made inside a right angle triangle having sides 3 cm, 4 cm and 5 cm when one of vertices of the square coincide with the vertex of right angle triangle –

Options:
A)

57679    cm2

B)

14449    cm2

C)

24 cm2

D)

None of these

Solution:

Ans: (b)

  

Knowledge Expert

· commented

· 1 Months ago

let suppose the side of the greatest square being inserted inside the right angled triangle is "a".
Area of the ABC =area ADB+area CDB
6=1/2*a*root2*h1+1/2*a*root2*h2
6=(h1+h2)*1/2*a*root2
From the diagram we know that (h1+h2)=5
6/5=1/2*a*root2
12/5=a*root2
144/25=a^2*2
a^2=144/50
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