Online Courses
Explore
Offline Courses
-
LAW
-
Judiciary
-
Management UG
-
CAT & OMETs
-
CUET
-
Design
-
Architecture
-
UPSC Law Optional
Explore
Test Series
Explore
Resources
-
LAW UG (5 Year LLB)
-
LAW UG (3 Year LLB)
-
LLM + LAW Officer
-
Judiciary
-
Management UG
-
Management PG
-
Design & Arch.
-
NTA CUET [UG]
-
Career Counselling
-
Current Affairs
-
UPSC LAW
Explore
Community
Explore
Join Us
Explore









Knowledge Expert
· commented
· 1 Months ago
See comprehensive solution:
Average speed = Total Distance / Total Time Taken
But we have only speeds S1 and S2
S1 = 20 km/hr
S2 = 30 km/hr
So now let us assume that the distance between a and b will be 60 km ( LCM of 20 and 30 )
D1 = 60 km
D2 = 60 km
Total Distance = D1 + D2 = 60 + 60 = 120 km
Now
T1 = D1/S1
T1 = 60/20 = 3 hr
T2 = D2/S2
T2 = 60/30 = 2 hr
Total Time = T1 + T2 = 3 + 2 = 5 hr
Now
Average Speed = Total Distance / Total Time = 120 / 5
Average Speed = 24 km/hr