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ROHIT JAGTAP

· started a discussion

· 1 Months ago

answer may be wrong 400-20=380 (Question:141330.0)

(a) The gross bearing capacity = qs.
net bearing capacity is qns,

depth of footing = Df

qs = qns + γDf

qns = qs — γDf

= 400 — 20 × 1 = 410 kN/m2

Question:

The gross bearing capacity of a 1.5 m wide strip footing at a depth of 1.0 m is 430 kN/m2. If \(\gamma\) = 20 kN/m2, what is the net bearing capacity?

Options:
A) 410 kN/m2
B) 420 kN/m2
C) 460 kN/m2
D) none of these
Solution:
Ans: (a) The gross bearing capacity = qs.

net bearing capacity is qns,

depth of footing = Df

qs = qns + \(\gamma\)Df

qns = qs — \(\gamma\)Df

= 400 — 20 × 1 = 410 kN/m2

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