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Deep Das

· started a discussion

· 1 Months ago

what about (6,2) is not a factor of 12. then option is coming is 3 pairs.

Question:
The product of two numbers is 2028 and their H.C.F. is 13. The number of such pairs is – 
Options:
A) 1
B) 2
C) 3
D) 4
Solution:
Ans: (b)


Ajay Bhardwaj

· commented

· 1 Months ago

brither,a & b must be coprime.that`s why 6,2 cant be taken.

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