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vipul kumar singh

· started a discussion

· 1 Months ago

answer is wrong (198223) (Question: 198223.0 )

answer must be A

Question:
If 4x = sec\(\theta\) and \(\cfrac{4}{x}\) = tan\(\theta\), then 8 \(\left (x^2 - \cfrac {1}{x^2} \right )\) is –
Options:
A) \(\cfrac{1}{16}\)
B) \(\cfrac{1}{8}\)
C) \(\cfrac{1}{2}\)
D) \(\cfrac{1}{4}\)
Solution:

Ans: (c)

you have evaluate the value of 8*(x^2−1/x^2)...............not only (x^2−1/x^2)...............


we have x^2 = sec^2theta/16 and 1/x^2 = tan^2theta/16


so, (x^2−1/x^2) = 1/16


so,   8*(x^2−1/x^2) = 8* 1/16 = 1/2

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