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Shashank Shah

· started a discussion

· 1 Months ago

Answer is correct (Question: 248636.0 )

Answer is right but explanation is wrong...Area of trapezium=half x sum of parellel sides x height == 1/2 x 6+ (6+2y) x h
And ATQ, area of ABEF= half the area of ABCD, i.e.,
6 x h = 1/2 x 1/2 ( 12+2y) x h
Now solve the equation you'll get the answer

Question:
ABCD is a trapezium in which AB is parallel to DC, AD = BC, AB = 6 cm, AB = EF and DF = EC. If two lines AF and BE are drawn in such a way that area of ABEF is half of ABCD. Find CE/CD.
Options:
A) \(\cfrac{1}{2}\)
B) \(\cfrac{1}{3}\)
C) \(\cfrac{1}{4}\)
D) \(\cfrac{1}{6}\)
Solution:

Ans: (b)


Prawin Mimicry

· commented

· 1 Months ago

True and Thank you..

VIJENDER DAHIYA

· commented

· 1 Months ago

very good

Paramount

· commented

· 1 Months ago

Yet to be approved!
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