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NAMI

· started a discussion

· 1 Months ago

2(4b)^2+3(4d)^2+4(4f)^2
= 4 [ 2(b^2)+3 (d^2)+4(f^2)] / 2(b^2)+3 (d^2)+4(f^2)
= 4

Question:
If  \(\cfrac{a}{b} = \cfrac{c}{d} = \cfrac{e}{f}\) = 4 then \(\cfrac{2a^2 + 3c^2 + 4e^2}{2b^2 + 3d^2 + 4f^2}\) = ?
Options:
A) 8
B) 16
C) 4
D) 18
Solution:
Ans: (b)


priyanka prakash

· commented

· 1 Months ago

its not 4,, its 4^2=16

Knowledge Expert

· commented

· 1 Months ago

Dear Student,
Your solution is totally wrong, go through the soution explored. 16 is the correct answer.
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