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Richa Pnjwani

· started a discussion

· 1 Months ago

answer differs from the solution (Question:959701.0)

the answer provided for the question is different from that of the solution kindly clear this doubt

Question:

If $3 x + \frac{2}{\sqrt{x}} = 1$ then $x - \sqrt{x}$ = ?

Options:

A)

$\frac{2}{\sqrt{3}}$

B)

\(\frac{-2}{3}\)

C)

$2 \sqrt{3}$

D)

$- 2 \sqrt{3}$

Solution:

$3 x + \frac{2}{\sqrt{x}} = 1$

$⟹$ $\frac{2}{\sqrt{x}} = 1 - 3 x$

$⟹$ $2 + \frac{2}{\sqrt{x}} = 3 - 3 x$

$⟹$ $2 (1 + \frac{1}{\sqrt{x}}) = 3 (1 - x)$

$⟹$ $2 (\frac{\sqrt{x} + 1}{\sqrt{x}}) = 3 (1 + \sqrt{x}) (1 - \sqrt{x})$

$⟹$ $\frac{2}{\sqrt{x}} = 3 (1 - \sqrt{x})$

$⟹$ $\frac{2}{3} = \sqrt{x} - x$

$⟹$ $x - \sqrt{x} = \frac{- 2}{3}$

Knowledge Expert

· commented

· 1 Months ago

Dear student,
We have done the required correction.

Regards
Team TR

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