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SUMIT PRAJAPATI

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· 1 Months ago

ANSWER 3 (Question:141887.0)

T(Equivalent) = Sqr root T2+M2
T2 Means t square

Question:

A circular shaft can transmit a torque of 5kNm. If the torque is reduced to 4kNm, then the maximum value of bending moment that can be applied to the shaft is

Options:
A) 1kNm
B) 2kNm
C) 3kNm
D) 4kNm
Solution:

Ans: (d) Meq = M±\(\sqrt{M\ ^2+T\ ^2}\)   .

here M =0 hence Meq = 4kN.

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