Ans should be 3/2 (Question:321045.0)

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Pampa Ghosh

· started a discussion

· 1 Months ago

Ans should be 3/2 (Question:321045.0)

Your solution is wrong

Question:

If $\frac{s i n θ + c o s θ}{s i n θ - c o s θ} = \frac{8}{3}$ then value of $\frac{t a n^{2} θ + 1}{t a n^{2} θ - 1}$ is:

Options:

$\frac{71}{24}$

$\frac{73}{24}$

$\frac{64}{9}$

$\frac{9}{24}$

Solution:

$\begin{matrix} \Rightarrow \frac{t a n θ + 1}{t a n θ - 1} = \frac{8}{3} \\ \frac{t a n^{2} θ + 1}{t a n^{2} θ - 1} = \frac{t a n θ + 1}{t a n θ - 1} + \frac{t a n θ - 1}{t a n θ + 1} \\ = \frac{8}{3} + \frac{3}{8} = \frac{64 + 9}{24} = \frac{73}{24} \end{matrix}$

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Ans should be 3/2 (Question:321045.0)

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