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Knowledge Expert
· commented
· 1 Months ago
Let consider,
ABCD is square and PQRSTUVW is octagon with equal sides constructed with in the square.
In order to have octagon with equal sides, we should have AP=QB=BR=SC=CT=….
Let AP=AW=x; (all sides which cut)
Let PQ = y; as all sides of octagon are equal, QR=RS=ST=TU=UV=VW=WP=y;
As the length of side of square is 2,
2x+y = 2 ------(1)
Applying Pythagoras to the right triangle APW, y2 = x2+x2 = 2x2
=> y= x√2 ------(2)
Solving (1) and (2):
2x+x√2 = 2 => x = 2/(2+√2) = √2/(√2+1)
=> y = x√2 = 2/(√2+1)
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