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OM PRAKASH MEENA

· started a discussion

· 1 Months ago

ans is correct (Question: 111093.0 )

its normal formula in trigno.

Question:
cos (A+B). cos (A-B) is given by :
Options:
A) cos2 A-cos2B
B) cos (A2 - B2)
C) cos2 A - sin2B
D) sin2 A - cos2B
Solution:
Ans: (c)

cos (A+B). cos (A-B) = cos2 A- sin2 B

Knowledge Expert

· commented

· 1 Months ago

Dear Student

Yes this question based on compound angle formula

cos(A + B) = cos A cos B − sin A sin B

cos(A − B) = cos A cos B + sin A sin B

cos(A + B).cos(A − B)= (cos A cos B − sin A sin B) (cos A cos B + sin A sin B)
cos ^2A. cos^2 B - sin^2 A sin^2B
cos ^2A(1-sin^2B)- sin^2A.sin^2B
cos^2A- cos^2A. sin^2B- sin^2A.sin^2B
cos^2A- sin^2B(cos^2A+sin^2A)
cos^2A- sin^2B

Keep learning keep solving
Best wishes
Team Toprankers

Knowledge Expert

· commented

· 1 Months ago

Yet to be approved!
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