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aman

· started a discussion

· 1 Months ago

ans is correct (Question: 108605.0 )

OB=3 , OM=1 so by pythagorus,
MB = root8 i.e 2root2
so AB = 2MB = 2*2root2 = 4root2

Question:

Two circles touches each other internally. Their radii are 2 cm and 3 cm. What will be the length of the largest chord of larger circle outside the inner circle?

Options:
A) \(2\sqrt[]{2}\) cm.
B) \(3\sqrt[]{2}\) cm.
C) \(2\sqrt[]{3}\) cm.
D) \(4\sqrt[]{2}\) cm.
Solution:
Ans: (d) 


Let the centre of the larger circle be O and the smaller circle be O'. P is the point where both the circles touch each other.

From the figure :

O O' = 1 cm(\(\because\) OP = 3 cm & O'P  = 2 cm)

OM = 1 cm(\(\because\) MP = 4 cm)

In \(\triangle\)OMB, 

MB = \(2\sqrt[]{2}\) cm

So, AB = \(4\sqrt[]{2}\) cm

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